An insurance company insured 2000 scooter drivers, 4000 car drivers and 6000 truck drivers. The probability of an accident is 0.01, 0.03 and 0.15 respectively. One of the insured person meets with an accident. What is the probability that he is a cooter driver?

Answer

`((1)/(6)xx(1)/(100))/((1)/(6)xx(1)/(100)+(1)/(3)xx(3)/(100)+(1)/(2)xx(15)/(100))=((1)/(6))/((1)/(6)+1+(15)/(2))=(1)/(1+6+45)=(1)/(52)`