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(1-cos2A+sin2A)/(1+cos2A+sin2A)=tanA...

`(1-cos2A+sin2A)/(1+cos2A+sin2A)=tanA`

Text Solution

Verified by Experts

The correct Answer is:
`=(2sinAcancel((sinA+cosA)))/(2cosAcancel((cosA+sinA)))`
NA
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