Let a(4, 2), B(6, 5) and C(1, 4) be the vertices of `Delta ABC`.
Find the coordinates of points Q and R on medians BE and CF respectively such that BQ : QE = 2 : 1 and CR : RF = 2 : 1.

Let a(4, 2), B(6, 5) and C(1, 4) be the vertices of Delta ABC . Find the coordinates of the point P on AD such that AP : PD = 2 : 1.

Let a(4, 2), B(6, 5) and C(1, 4) be the vertices of Delta ABC . The median from A meets BC at D. Find the coordinates of the point D.

Let A (4, 2). B (6, 5) and C (1, 4) be the vertices of Delta ABC. i The median from A meets BC at D. Find the coordinates of point D.

Let A (4, 2), B (6, 5) and C (1, 4) be the vertices of ΔABC.The median from A meets BC at D Find the points which divide the line segment BE in the ratio 2 : 1 and also that divide the line segment CF in the ratio 2 : 1.

If P(1,2), Q(4,6), R(5,7) and S(a, b) are the vertices of a parallelogram P Q R S , then

Let a(4, 2), B(6, 5) and C(1, 4) be the vertices of Delta ABC . What do you observe ? [Note : The point which is common to all the three medians is called the centroid and this point divides each median in the ratio 2 : 1.]

If A(-2, -1) B(a, 0) C(4, b) and D(1 , 2) are the vertices of a parallelogram. Find a and b

The vertices of a Delta ABC are A (-3,2) , B (-1,-4) and C (5,2) . If M and N are the mid - points of AB and AC respectively show that 2 MN = BC .

The points A (6, 1), B (8, 2), and C 9, 4) are the three vertices of a parallelogram ABCD. If E is the midpoint of DC, find area of Delta ADE.