Home
Class 9
MATHS
In, ABC and ABD are two triangles on the...

In, ABC and ABD are two triangles on the same base AB. If line- segment CD is bisected by AB at O, show that ar (ABC) = ar (ABD).

Promotional Banner

Topper's Solved these Questions

  • AREA OF PARALLELOGRAMS AND TRIANGLES

    SUBHASH PUBLICATION|Exercise EXERCISE 11.4|3 Videos

  • AREA OF PARALLELOGRAMS AND TRIANGLES

    SUBHASH PUBLICATION|Exercise EXERCISE 11.2|6 Videos

  • APPENDIX A

    SUBHASH PUBLICATION|Exercise EXERCISE A 1.4|10 Videos

  • CIRCLES

    SUBHASH PUBLICATION|Exercise EXERCISE 12.6|7 Videos

Similar Questions

Explore conceptually related problems

In the given figure, ABC and ABD are two triangles on the same base AB . If line - segment CD is bisected by AB at O, show that ar (ABC) = ar (ABD)

In Fig , ABC and DBC are two triangles on the same base BC. If AD intersects BC,at O , show that (ar(ABC))/(ar(DBC))=(AO)/(DO)

In the figure given below, ABC and DBC are two triangles on the same base BC. If AD intersects BC at O , show that (ar(Delta ABC))/(ar(Delta DBC)) = (AO)/(DO) .

ABC and DBC are two isosceles triangles on the same base BC. Show that ABD = ACD.

In the figure ABC and DBC are two triangles on the same base BC. If AD intersects BC at 0, show that ("Area"(DeltaABC))/("Area"(DeltaDBC))=(AO) /(DO) .

ABC and DBC are two isosceles triangles on the same base BC. Show that, triangleABD = angleACD

Triangle ABC and parallelogram ABEF are on the same base, AB as in between the same parallels AB and EF. Prove that ar (DeltaABC) = 1/2 ar(|| gm ABEF)

DeltaABC and DeltaDBC are two isosceles triangles on thesame base BC (see figure). Show that /_ ABD = /_ ACD.

In the figure 11.23, E is any point on median AD of a Delta ABC. Show that ar (ABE) = ar (ACE).