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The position coordinate of a moving part...

The position coordinate of a moving particle is given by `x=6+18t+9t^(2)` ('x' in 'm' and 't' is 's') what is its velocity at `t=2s`?

Text Solution

Verified by Experts

Given `x=6+18t+9t^(2)`
`v=18+18(t)`
'v' at t = 2s will be `v=18+18(2)=54ms^(-1)`
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Knowledge Check

  • The co-ordinates of moving particle at any time t are given by x = at^(2) and y = b t^(2) . The velocity magnitude of the particle :

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    D
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