A particle moves in a straight line such that its displacement is `s^(2)=t^(2)+1` Find.
(ii) acceleration as a function of 's'

Explanation

Differentiate (i) w.r.t to 't' we write
`(d^(2)s)/(dt^(2))=((s)(dt)/(dt)-t(ds)//(dt))/(s^(2))`
`"i.e., "a=(s-tv)/(s^(2))`
`"i.e., "a=(s-(sv)v)/(s^(2))`
`a=(s-(s(s^(2)-1))/(s^(2)))/(s^(2))=(1)/(s^(3))`