Discuss different cases, to find final velocities for two bodies in the below expression for `v_(1f)=((m1-m2)v1i)/(m1+m2) and v_(2f)=(2m1v1i)/(m1+m2)`

Solve : ( 4)/( m+ 2) - (1)/( m+3) = (4)/( 2m +1)

Solve the following linear equations. m-(m-1)/2=1-(m-2)/3

Without solving, find the value of m for which the zeros are equal for f(x) = x^(2) + 2 (m - 1) x + m + 5

The SI unit of energy is J=kg m^(2)s^(-2) , that of speed v is ms^(-1) and of acceleration a is ms^(-2) . What of the formulae for kinetic energy (k) given below can you rule out on the basis of dimensional arguments (m stands for the mass of the body) : (a) K = m^(2)v^(2) (b) K = (1/2)mv^(2) ("c") K= ma (d) K = (3/16)mv^(2) (e) K=(1/2)mv^(2)+ma

A particle of mass M at rest decays into two masses m_(1) and m_2 with non zero velocities. The ratio of de-Broglie wavelengths of the particles (lamda_(1))/(lamda_(2)) is

If m and n are degree and other of (1+y_(1)^(2))^(2//3)=y_(2) , then tha value of (m+n)/(m-n) is

Find the value of m or p in the following quadratic equations, which have equal roots. (v) x^(2)-(m+1)x+m=0

Write the nth term of the A.P. (1)/(m) , (1+m)/(m) , (1+2m)/(m) ,…

Find the least positive integer m such that ((1+i)/(1-i))^(4m)=1 .