A cart is used to lower vertically, a block of mass 10 kg over a distance of 0.30 m, at a constant downward acceleration of `((g)/(4))`. Find the work done by the cart on the block.

Explanation

`m=10kg,d=0.30m`
`a=(g)/(4)=(9.8)/(4)=2.45ms^(-2)`
Tension with string T = mg - ma
i.e. `T=M(g-a)=10(9.80-2.45)=73.5N`
Work done by the cart on the block `=W=T.d.cos180^(@)`
`=73.5xx0.3xx-1`
`=-22.05J`