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A body of mass 5 kg, initially at rest, ...

A body of mass 5 kg, initially at rest, moves under the action of an applied force of 15N on a horizontal surface with a coefficient of friction 0.25. Calculate
(a) Work done by the force (b) Work done by friction
(c ) Work done by net force (d) Change in kinetic energy in 5s.

Text Solution

Verified by Experts

Given, `m=5kg,t=5s`,
Force of friction `f=mumg=0.25xx5xx9.8=12.25N`
Net force on the body `=15-12.25=2.75N`
Acceleration of body = `(2.75)/(5)=0.55ms^(-2)`
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