The maximum and minimum distance of a comet from the sun are `1.4xx10^(12)`m and `7xx10^(10)`m . If its velocity nearest to the sun is `6xx10^(4)ms^(-1)`, then what is the velocity at the farthest position ? Assume the path of the comet as circular.

Explanation

`I_1=1.4xx10^(12)m,d_2=7xx10^(10)m`
`v_1=6xx10^(4)ms^(-1),v_2`=?
Since angular momentum is conserved
`m_pr_pv_p=m_pr_av_a`
`(v_p)/(v_A)=(r_A)/(r_p)` i.e, `(6xx10^4)/(V_a)=(7xx10^(10))/(1.4xx10^(12))`
i.e `v_A=(6xx10^4xx1.4xx10^(12))/(7xx10^(10))" ":." "v_A=1.2xx10^(6)ms^(-1)`