Calculate the angular speeds of the second, minute and hour hands of a 12 hour dial clock.

Explanation

(1) `omega` of the second that `=(2pi)/(T)=(2xx3.142)/(60)=1.047xx10^(-1)rads^(-1)`
(2) `omega` of the minute hand `=(2xx3.142)/(60xx60)=1.745xx10^(-3)rads^(-1)`
(3)`omega` of the hour hand=`(2xx3.142)/(12x3600)=1.454xx10^(-4)rad^(-1)`