A solid cylinder rolls up an inclined plane of angle of inclination `30^(@)`. At the bottom of the inclined plane the centre of mass of the cylinder has a speed of `5ms^(-1)`
How long will it take to return to the bottom ?

Explanation

But`a=(gsintheta)/(1+(K^2)/(R^2))` i.e `K=(R^2)/2,a=(2gsintheta)/3`
hence `0=u-at_a` or `t_a=u/a=(5xx3)/(2xx10xxsin30^(@))=3/2`