A solid rolls down two different inclined planes of the same heights but different angle of inclination.
Will it reach the bottoms with the same speed in each case ?

Explanation

Linear KE=`1/2mv^2` Rotational K.E`=1/2Iomega^2=1/5mv^2`

`:. T.E=1/2mv^2+1/5mv^2=7/(10)mv^2` but T.E=mgh
`:. Mgh=7/(10)mv^2` i.e `v=sqrt((10)/(7)gh):'vproph`
v is the same for both the cases. Yes, the solid sphere will reach the bottom with the same speed both the cases.