Find the amount of heat required to convert 10 kg ice at `-10^(@)C` to water at `50^(@)C`. Given specific heat of ice `2100Jkg^(-1)K^(-1)`, specific heat of water `4200Jkg^(-1)K^(-1)` and latent heat of ice `3.36xx10^5Jkg^(-1)`

Explanation

Quantity of heat required to convert ice at `-10^(@)C` to water at `50^(@)C`
`Q=M_"ice"S_("ice")(0-(-10)+M_("ice")L+M_WS_W(50-0)`
i.e `Q=10xx2100xx10+10xx3.36xx10^5+10xx4200xx50`
i.e `Q=2.1xx10^5+33.6xx10^5+21xx10^5`
i.e, `Q=56.7xx10^5J`
or `Q=5.67xx10^6J` of heat is required