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Deduce the expression for horizontal ran...

Deduce the expression for horizontal range of a projectile. For what angle of projection does horizontal range become maximum?

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Obtain an expression for Horizontal Range of a projectile.

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Knowledge Check

  • At what angle an object be projected so that the horizonal range is equal to the maximum height ?

    A
    `tan^( -1)1`
    B
    `tan^( -1)2`
    C
    `tan^( -1)3`
    D
    `tan^( -1)4`

  • If R is the range and T is the time of flight of a projectile then the angle of projection is given by :

    A
    `tantheta=(g T^(2))/(R)`
    B
    `tantheta=(g T^(2))/(2R)`
    C
    `tantheta=T^(2)/(Rg)`
    D
    `tantheta=T^(2)/(2Rg)`

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