Find the magnitude of magnetic induction at a point 0.06m from the centre and along the axis of a circular coil carrying a current of 2 A. Also calculate the magnitude of magnetic induction at the centre of the coil.
Given: Number of turns in the coil = 20
Mean radius of the coil = 0.05 m.

Explanation

Given `I=2A, r=5 times 10^(-2)m, n=20, d=6 times 10^(-2)`
We know that the magnetic field at the centre of the coil,
`" "B=(mu_(0)/(4pi))((2pini)/r)T`.
i.e., `" "B=(10^(-7) times 2 times 3.142 times 20 times 2)/(5 times 10^(-2))=50.272 times 10^(-5)T`
Magnetic fields at point `B^(')=(10^(-7)2pini)/(r(1+(x/r)^(2))^(3//2))`
i.e., `" "B^(')=(B)/((1+(x/r)^(2))^(3//2))`
`" "B^(')=(50.272 times 10^(-5))/(1+(0.06/0.05)^(2))^(3//2)=(50.272 times 10^(-5))/3.811`
`" "B^(')=13.19 times 10^(-5)T.`