An `alpha-` particle of mass `6.65 times 10^(-27)kg` is travelling at right angles to a magnetic field with a speed of `6 times 10^(5)ms^(-1)`. The strength of the magnetic field is 0.2 T. Calculate the force on the `alpha-` particle and its acceleration.

Explanation

Force on a charged particle,
`" "F_(m)=Bqvsintheta`
Here`" "m=6.65 times 10^(-27)kg, q_(alpha)=2e=2 times 1.6times 10^(-19)C`
`" "q_(alpha)=3.2 times 10^(-19)C`
`" "B=0.2 T, v=6 times 10^(5)ms^(-1)`
`therefore " "F_(m)=0.2 times 3.2 times 10^(-19) times 6 times 10^(5) times sin90^(@)`
`" "=3.84 times 10^(-14)N`
Acceleration of the `alpha-` particle, `a=F_(m)/m=(3.84 times 10^(-14))/(6.65 times 10^(-27))`
`" "a=5.77 times 10^(12)ms^(-2)`