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A domain in a ferromagnetic substance is...

A domain in a ferromagnetic substance is in the form of a cube of volume `10^(-18)m^(3).` Calculate the number of atoms present in the given volume and a hypothetical dipole moment and magnetisation of the domain ( given density of the substance `7.9xx 10^(3) "kgm"^(-3)` molecular mass 55g / mole and dipole moment of each atom is `9.2 xx 10^(-24) "Am"^(2))`.

Text Solution

Verified by Experts

Given volume of the cube = `10^(-18) m^(3)`
mass = (volume ) (density )
`= 10^(-18) m^(3)xx7.9xx 10^(3) "kg m"^(-3)`
i.g., `" " m = 7.9 xx 10^(-15) ` kg
Number of atoms = `(7.9 xx 10^(-15) xx 6.0235 xx 10^(23))/(55xx10^(-3))`
`= 0.865 xx 10 ^(11)`
=` 8.65 xx 10 ^(10)` atoms
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