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S.T an LC oscillator executes SHM and he...

S.T an LC oscillator executes SHM and hence obtain an expression for the angular frequency of oscillation.

Text Solution

Verified by Experts

Applying KVL we get,
`v_(c)-L(di)/(dt)=0`
i.e, `(q)/(C)-L(di)/(dt)=0`
`therefore i=-(dq)/(dt),(di)/(dt)=(-d^(2)q)/(dt)`
`therefore (q)/(C)+L(d^(2)q)/(dt^(2))=0`
or `(d^(2)q)/(dt^(2))+(1)/(LC)q=0` which is similar to `(d^(2)x)/(dt^(2))+omega_(o)^(2)x=0`
`therefore omega_(0)^(2)=(1)/(LC)`
i.e., `omega_(0)-(1)/(sqrt(LC))andq=q_(m)cos(omega_(0)t+phi)`
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