A sinusoidal current is represented by the equation `I=2sin100pit`. Calculate
Current at `t=(1)/(16)s`.

Explanation

Given, `I=2sin100pit" "...(1)`
This equation is of the form `I=I_(0)sinomegat" "...(2)`
Comparing equations (1) and (2), we note that
Peak value `I_(0)=2Aand2pif=100pi`
i.e., `f=50Hz`
Consider `I=2sin2pft=2sin.(2pi)/(T)xxt" at "t=(T)/(16)S,I=2sin.(2pi)/(T)xx(T)/(16)`
`therefore` current at `t=(1)/(16)s,I=2sin((pi)/(8))=2sin(22.5^(@))=2(0.3827)=0.7654A`