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A 44 mH inductor is connected to a 220 V...

A 44 mH inductor is connected to a 220 V, 50Hz ac supply. Determine the r.m.s value and peak value of the current in the circuit.

Text Solution

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Given, `L=44xx10^(-3)H,v_(rms)=220V,f=50Hz`
`X_(L)=2pifL=2xx3.14xx50xx44xx10^(-3)Omega`
i.e., `X_(L)=13.852Omega`
`i_(rms)=(v_(rms))/(X_(L))=(220)/(13.825)=15.9A`
`i_(p)=sqrt(2)i_(rms)R=1.414xx15.9=22.48A`
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