A `100xx10^(-6)` capacitor is series with a `40Omega` resistance is connected to a 110 V, 60 Hz supply.
What is the maximum current in the circuit?

Explanation

Given `C=100xx10^(-6)=10^(-4)F,R=40Omega,v_(rms)=110V,f=50Hz`
using `X_(C)=(1)/(2pifC)=(1)/(2xx3.142xx60xx10^(-4))=26.52Omega`
and `Z=sqrt(1600+703.44)=48.0Omega`
`i_(m)=(v_(m))/(Z)=(1.414xx110)/(48)=3.24A`