A `100xx10^(-6)` capacitor is series with a `40Omega` resistance is connected to a 110 V, 60 Hz supply.
What is the time lag between current maximum and the voltage maximum?

Explanation

`tanphi=(X_(C))/(R)=(26.52)/(40)=0.6630`
i.e., `phi=33^(@)32^(1)~~32.53^(@)~~32.5^(@)`
Phase angle `phi=omegat,omega=2pixx60=120pi`
`therefore t=(phi)/(omega)=(32.53cancelpi)/(180xx2cancelpixx60)`
i.e., `t=1.50xx10^(-3)s`
i.e., `t=1.50ms`