A circuit containing an inductor of 80mH inductance and a capacitor of `60muF` capacitance in series, is connected to a 230V, 50Hz supply. The resistance of the circuit is negligible.
Obtain the r.m.s values of potential drop across each element.

Explanation

Given : `L=80xx10^(-3)H,C=60xx10^(-6)F,v_(rms)=230V,f=50Hz,R=0`
Using, `X_(L)=2pifL=2xx3.142xx50xx8xx10^(-2)`
we get, `X_(L)=25.14Omega`
and `X_(C)=(1)/(2pifC)=(1)/(2xx3.142xx50xx6xx10^(-5))Omega`
i.e., `X_(C)=53.04Omega`
Effective reactance = `53.04-25.14=27.9Omega`
`Z=X_(C)-X_(L)=27.9Omega`
`v_(Lrms)=i_(rms)X_(L)`
`=8.24xx25.14V`
`=207.1V`
`v_(Crms)=i_(rms)X_(C)`
`=8.24xx53.04V`
`=437.0V`
`v_(R)=i_(rms)R`
`=8.24xx0`
= 0