Compare the intensity of second secondary maximum with the intensity of central maximum for the single slit Fraunhofer diffraction pattern.

Compare the intensity of first secondary maximum with the intensity of central maximum for the single slit fraunhoffer diffraction pattern.

How does width of central maximum vary with the width of the slit used?

Calculate the angular width of 2^(nd) secondary maximum and fourth dark fringe in the diffraction pattern obtained due to a single slit of width 10^(-5) m illuminated by a wavelength of light 541 nm.

Compare width of slits with the intensity and hence amplitude of the waves.

Yellow light ( lambda=6000Å ) illuminates a single slit of width 1xx10^(-4)m . Calculate : (i) the distance between the two dark lines on either side of the central maximum, when the diffraction pattern is viewed on a screen kept 1.5m away from the slit, (ii) the angular spread of the first diffraction minimum.

Light of wavelength 600nm is incident normally on a slit of width 0.2 mm. The anuglular width of central maxima in the diffraction pattern is (measured from miminum to minimum )

A single slit Fraunhoffer diffraction pattern is formed with white light. For what wavelength of light the third secondary maximum in the diffraction pattern coincides with the second secondary maximum in the pattern for red light of wavelength 6500 overset@A ?

Light of wavelength 6328 Å incident normally on a slit having a width of 0.2 mm The width of the central maximum, measured from minimum to minimum of the diffraction pattern on a screen 9.0 metres away will be about