In young's double slit experiment, the total width of 10 fringes is observed as `2xx10^(-3) m` and the slits are separated by the distance of `2xx10^(-3) m` . Find the distance between the slits and the screen, when a light of wavelength 6000 `overset(@)A` is used.

Explanation

Given `10 beta = 2xx10^(-3) m` so that `beta=0.2 xx10^(-3) m `
`d=2 xx10^(-3), lambda=6xx10^(-7) m, D=?`
We know that `beta=(lambdaD)/(d)`
i.e. `0.2xx10^(-3)=(6xx10^(-7))/(2xx10^(-3)) D`