If the limit of resolution of the eye is 1' of an arc then calculate its resolving power.

Explanation

Given , `d=1=(1/60)^@=(1/60)(3.142)/(180)"rad"`
`dtheta=2.91xx10^(-4)` rad.
but `R.P=(1)/(d theta)=(1)/(2.91xx10^(-4))=3.436xx10^3 "rad"^(-1)`