Two polaroid sheets are placed in such way that one is inclined at an angle of `47^@` and the second at `63^@`. If the intensity of incident light is `1000 Wm^(-2)`, then find the intensity of light at the transmitted ends of the sheets.

Explanation

`I=I_(0) cos^2 theta`
`1=1000xxcos^2 47^@`
`=1000xx(0.6807)`
`=680.7 Wm^(-2)` through crystal (1)
For the second crystal,
`I'=I cos^2 63^@`
`=680.7xx(0.4560)^2`
`=140.3 Wm^(-2)`