Arrive at the expression for the magnetic flux density at the centre of the circular path of an electron in terms of magnetic moment.

Explanation

We know that
`B=((mu_(0))/(4pi))((2pi)/(r))i`
Multiplying and dividing by `r^(2)` we get ,
`B=((mu_(0))/(2pi))((ipir^(2))/(pir^(2)))`
i.e., `B=(mu_(0)m)/(2pir^(3))`
where , `m=i(pir^(2))` is known as the magnetic moment associated with the current loop.