A radioactive sample of half life `T_((1)/(2))` contains 1000 nuclei. How many members will be left after a time `t=(T//8)`?

Explanation

`N_(0)=1000, lambda =(0.693)/(T(1)/(2)),t=(T)/(8),N_(0)=N2,`
`n=(t)/(T)=(1)/(8),N=(1000)/(2^(1//3))`2
logN`=3.0000-(1)/(8)(0.3010)=3.0000`
`logN=(-0.03763)/(2.96237),`
` therefore N=916.8`
Number of nuclei left after a time `t=(T)/(8)=916.8`