Calculate the specific binding energy of the nucleus of `._(7)^(14)N`. Given the rest mass of nucleus of `._(7)^(14)N=14.00307`u, the rest mass of proton =1.00783 u and the rest mass of neutron=1.00867 u.

Explanation

Calculation of mass defect:
`Deltam=Zm_(p)+(A-Z)M_(n)-M`
`Deltam=7xx1.00783+7xx1.00867-14.00307=0.11243 u`
Calculation of binding energy:
For 1 u (lamu), binding energy, `Delta E =931.5 MeV`
For `0.11243 u` (lamu), `Delta E=0.11243xx931.5 MeV`
`=104.72854 MeV`
Binding energy per nucleon `=(BE)/(A)=7.4861 `MeV/nucleon