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If tan(pi//4+theta)+""tan(pi//4-theta)=l...

If `tan(pi//4+theta)+""tan(pi//4-theta)=lambdasec2theta,t h e m` `3` (b) `4` (c) `1` (d)`2`

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Given,
`tan(pi/4+theta)`
`=(tan(pi/4)+tantheta)/(1−tan(pi/4)tantheta)`
`=(1+tantheta)/(1−tantheta)`
Similarly,
`tan(pi/4−theta)=(1−tantheta)/(1+tantheta)`
So,LHS
`=(1+tantheta)/(1−tantheta)+(1−tantheta)/(1+tantheta)`
...
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