For a CE transistor amplifier, the audio signal across the collector resistance of `2kOmega` is 2V. Suppose the current amplification factor of the transistor is 100, find the input signal voltage and base current, if the base resistance is 1 k`Omega`.

Explanation

Given : `beta = 100 . R_(C) = 2 xx 10^(3) Omega, V_(0) = 2V.`
`R_(B) = 1 xx 10^(3) Omega`
By `" " beta = (I_(C))/(I_(B))` where `I_(C) = (V_(0))/(R_(C)) = (2)/(2 xx 10^(3))`
i.e., `" " I_(C) = 1 xx 10^(-3)` A
Hence `" " I_(B) (I_(C))/(beta) = (1 xx 10^(-3))/( 100 ) = 1 xx 10^(-5)` A
Input signal voltage `V_(i) = (V_(0))/(A)`
Where `" " A_(v) = |-beta (R_(C))/(R_(B))|`
i.e.,` " "A_(v) = (100 xx 2 xx 10^(3))/(1 xx 10^(3)) = 200`
and `" " V_(i) = (2V)/(200 ) = 10^(-2)` V
i.e.,`" " V_(i) = 0.01 `V or 10 m V.