Compute the mass of one molecule and the molecular mass of `C_(6)H_(6)` (benzene). (At mass of C=12, H=1 u).

Explanation

Molecular weight of `C_(6)H_(6) = 6 xx 12 + 6 xx 1 = 78 g`.
Mass of 1 molecule `=78/(6.022 xx 10^(23)) = 12.94 xx 10^(-23)`
`g= 1.294 xx 10^(-22)`g