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1 M solution of NaNO(3) has density 1.25...

1 M solution of `NaNO_(3)` has density 1.25 g `cm^(-3)`. Calculate its molarity. (Mol. Weight of `NaNO_(3) = 85 g mol^(-1))`.

Text Solution

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Mass of solution = Volume of solution x density of solution
Mass of solution = 1000 `cm^(3) xx 1.25 g cm^(-3) = 1250` g
Mass of solute = 85 g, Mass of solvent =`1250 - 85= 1165` g
`m = W_(a)/M_(a) xx 1000/(W_(A)"in grams") = 85/85 xx 1000/1165` = 0.858 m.
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