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Calculate the normality of oxalic acid s...

Calculate the normality of oxalic acid solutions containing 0.895 g crystals in `250 cm^(3)` of its solutions.

Text Solution

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Molecular formula of oxalic acid crystals `=H_(2)C_(2)O_(4). 2H_(2)O = 126` Equivalent mass `=("molecular mass")/("basicity") = 126/2 = 63`
Mass/ lit = N x g . Eq. mass.
`("Mass")/(250 ml) = (N xx g. eq. "mass")/(4) rArr N xx g. eq."mass" = (4 xx "mass")/(250 ml)`
= 0.0568
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