How many atoms of oxygen are present in 300 g of `CaCO_(3)`?

Explanation

Given formula mass of `CaCO_(3) = 100`g
Now, 1 mole of `CaCO_(3)` contain = 3 mole of 0 atoms.
100 g of `CaCO_(3)` contain `= 3xx 6.02 xx 10^(23)` 0 atoms.
`therefore 300 g` of `CaCO_(3)` contain 0 atoms `=(3 xx 6.023 xx 10^(23))/(100)`
`=54.207 xx 10^(23)` oxygen atoms.