Calculate the wave number, wavelength and frequency first line of hydrogen spectrum or Calculate the maximum wave length of a line in the Lyman series.

Explanation

First line is Lyman Series, where `n_(1) = 1, n_(2) = 2`. Maximum wave length corresponds to minimum frequency i.e., `n_(1) = 1, n_(2) = 2.`
Wave number `=barv=R[1/(n_(1)^(2))-1/(n_(2)^(2))]`.
R = Rydberg constant = `1.097xx10^(+7)m.n_(1)=1n_(2)=2`
`barv=1.097xx10^(+7)[1/(I^(2))-1/(2^(2))]`
Wave length `lamda=0.8227xx10^(7)=8.227xx10^(6)m^(-1)`
But `barv=1/(lamda)`
`thereforelamda=1/v=1/(8.27xx10^(6)m^(-1))=0.1215xx10^(-6)m=1.215xx10^(-17)m`
Frequency `lamda=C/(barv)=(3xx10^(8)m//s)/(1.215xx10^(-7)m)=2.469xx10^(-15) Hz` or `s^(1)`