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A major line in an atomic emission spect...

A major line in an atomic emission spectrum occurs at 450 nm. Find the energy decrease, as this photon is emitted.

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`E=hv=(hc)/lamda=(6.626xx10^(-34)Jsxx3xx10^(8)ms^(-1))/(450xx10^(-9)m)=4.417xx10^(-19)J`
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SUBHASH PUBLICATION-STRUCTURE OF ATOM-NUMERICAL PROBLEMS AND ANSWERS
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