Calculate the de Broglie wavelength of
an electron of mass `9.11 xx 10^(-31)` kg and moving with a velocity of `1.0xx 10^(6) ms^(-1)`

Explanation

`lamda=h/p=h/(m_(e)V)becauselamda=(6.626xx10^(-34))/(9.11xx10^(-11)xx1.0xx10^(6))`
`h=6.626xx10^(-34)Js,` me`=9.11xx10^(-34)`kg `v=1.0xx10^(6)ms^(-1)`
`1=0.7273xx10^(-9)m=0.7273` nm.