Calculate the momentum of a moving particle which has a de- broglie wavelength of 200 pm.

Explanation

We know, `lamda=h/(mv)` or `mv=h/lamda`
Where `h = 6.626xx 10^(-34) Js = 6.626xx 10^(-34) kg m^(2) s^(-1)`
`lamda=200`pm `=2xx10^(-10)m`
Momentum, `mv=h/(lamda)=(6.626xx10^(-34)kgm^(2)s^(-1))/(2xx10^(-10)m)=3.313xx10^(-24)kgms^(-1)`