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When an ideal gas expands in vaccum, the...

When an ideal gas expands in vaccum, there is neither absorption nor evolution of work ? Why ?

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It is because no work is done.
i.e., `w = 0 " "w = -p_(ext) xx Delta V = 0 xx Delta V = 0`.
In `Delta U = q + w`
q = 0 because the gas chamber is insulated. `Delta U = 0 + 0 = 0`.
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