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Calculate the standard free energy chang...

Calculate the standard free energy change `Delta G^(@)` for the reaction,
`2HgO(s) rarr 2Hg(l) + O_(2)(g)`
`Delta H^(@) = 91 kJ mol^(-1)` at `298 K, S_((HgO))^(@) = 72.0 JK^(-1) mol^(-1)`.

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`Delta S = 2S_(Hg)^(@) + S_((O_(2)))^(@) - 25_(HgO)^(@)`
`= (2 xx 77.4 + 205 - 2 xx 72.0) JK^(-1) mol^(-1) = 215.8 JK^(-1) mol^(-1)`
`Delta G^(@) = Delta_(r )H^(@) - T Delta_(r )S^(@)`
`= 91 kJ mol^(-1) - (298 xx 21538)/(1000) xx kJ mol^(-1)`
`= (91 - 64.3) kJ mol^(-1) = 26.69 kJ mol^(-1)`
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