Calculate the entropy change involved in convertion of 1 mole of water at 373 K to vapours at the same temperature. Latent heat of vaporisation of water `= 2.257 kJ g^(-1)`.

Explanation

`k = 1.8 xx 10^(-7)`
`Delta H = 2.257 xx 18 kJ = 40.626 kJ mol^(-1)`
`Delta S_("vap") = (Delta H_(vap))/("B.pt. in kelvin") = (40.626 kJ mol^(-1))/(373 K) = 0.1089 kJ mol^(-1) = 108.9 kJ^(-1) mol^(-1)`.