Calculate `Delta H_(f)` of HCl if bond energy of H-H bond is 437 kJ Cl-CL bond is 244, and H-C is `433 kJ mol^(-1)`.

Explanation

`(1)/(2)H_(2)(g) + (1)/(2)Cl_(2)(g) rarr HCl(g)`
`Delta H = (1)/(2)B_(H-H) + (1)/(2)B_(O-O) = (1)/(2) xx 437 + (1)/(2) xx 244 - 433`
`= 218.5 kJ + 122 kJ - 433 kJ = -92.5 kJ mol^(-1)`.