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Calculate the Gibb's energy change for t...

Calculate the Gibb's energy change for the formation of propane, `C_(3)H_(8(g))` at 298 K. Given that
`Delta_(f)H` for propane `= -103.85 kJ mol^(-1)`
`Delta S` for the reaction is `- 269.74 JK^(-1)`.

Text Solution

Verified by Experts

The formation of `C_(3)H_(8(g))` is represented by `3C_("(graphite)") + 4H_(2(g)) rarr C_(3)H_(8(g))`
`Delta S = -269.74 JK^(-1)`
`Delta_(f)G = Delta_(f)H - T Delta S`
`= -103.85 xx 10^(3)J - 298 K xx (-269.74 JK^(-1))`
`= -23467.48 J` (or) `-23.467 KJ`
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