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Equilibrium constant of a reaction is 0.008. Calculate the standard Gibb's energy change at 298 K.

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`Delta G^(@) = -2.303 RT log K`
`= -2.303 RT log K`
`= -2.303 xx 8.314 xx 298 log(8 xx 10^(-3))`
`= -2.303 xx 8.314 xx 298 (0.9031 - 3)`
`= -2.303 xx 8.314 xx 298 (-2.0969) = 11964 J = 11.964 kJ mol^(-1)`
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