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Calculate Delta H for the reaction 2O(2)...

Calculate `Delta H` for the reaction `2O_(2)(g) rarr 3O_(2)(g)` at 298 K and 1 atmosphere pressure given that `Delta U = -287.9 kJ` and `R = 8.314 JK^(-1) mol^(-1)`.

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As per the equation `Delta H = Delta U + Delta n RT`, where
`Delta U = -287.9 kJ, Delta n = (3-2) = 1, R = 8.314 JK^(-1) mol^(-1), T = 298K , Delta H = ?`
`Delta H = -287.9 kJ + 1 xx 8.314 xx 10^(-3) KJ K^(-1) mol^(-2) xx 298 K`
`= -285.4 kJ mol^(-1)`
Change in enthalpy for the reaction `= -285.4 kJ mol^(-1)`.
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