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Delta G^(@) of a reaction is 120 kJ mol^...

`Delta G^(@)` of a reaction is `120 kJ mol^(-1)`. Calculate the `K_(p)` at `20^(@)C`.

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`Delta G^(@) = -2.303 RT log_(10) K_(p)`
`-120,000 = -2.303 xx 8.314 xx 293 xx log_(10)K_(p)`
`log_(10)K_(p) = (-120,000)/(-2.303 xx 8.314 xx 293)`
`log_(10)K_(p) = 21.39`
`K_(p) = "antilog" 21.39`
`- 2.455 xx 10^(21)`
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