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Calculate pH of 0.005 M H(2)SO(4)....

Calculate pH of 0.005 M `H_(2)SO_(4)`.

Text Solution

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`pH=-log_(10)[H^(+)]-log_(10)[0.005xx2]=-log_(10)[0.01]=-log_(10)[1xx10^(-2)]`
pH = `2-log1=2-0=2`.
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